c++ - Why does GCC generate 15-20% faster code if I

A binary property list with the following parameters is expected as reply: key type description; data: data: OPTIONS * RTSP/1.0 CSeq: 3 User-Agent: iTunes/10.6 (Macintosh; Intel Mac OS X 10.7.3) AppleWebKit/535.18.5 Client-Instance: 56B29BB6CB904862 DACP-ID: 56B29BB6CB904862 Active-Remote: 1986535575 e8 00 00 00 00 00 00 00 00 41 49 52 UPDATE 2: We can take -Os out of the picture. The following times are obtained by compiling with-O2 -fno-omit-frame-pointer 0.37s-O2 -fno-align-functions -fno-align-loops 0.37s-S -O2 then manually moving the assembly of add() after work() 0.37s-O2 0.44s. It looks like to me the distance of add() from the call site matters a lot. I have tried perf, but the output of perf stat and perf report A quick update on distro adoption status: Debian unstable, Gentoo, Fedora devel and Arch GNU/Linux distributions provide their users with an up-to-date 0.8.0 package.. OS X users are covered as well: with Gentoo Prefix you can easily have either 0.8.0 or the current git version (-9999); same about Homebrew: just update and brew install [--HEAD] openocd (where the optional –HEAD parameter Now, as we know, an ARM instruction has 32 bits in which to encode the instruction type, condition, operands etc. In group one instructions there are twelve bits available to encode immediate operands. Twelve bits of binary can represent numbers in the range 0..4095, or -2048..+2047 if we treat them as signed. 0b - binary & - decimal. A constant can also be specified as a string: 'ccc' / "ccc" When expecting an address, the debugger first tries to identify the input as a constant, then as register name, and then as a symbol. So symbol names, such as 'r1' 'a0', should be preceded by a '$' sign. An address range is defined as start_range end_range.

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